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Answer: Option B

Explanation:

Given change of current di/dt = 20*10^-3amperes./10^-6 s 

Inductance = 8*10^-6henry.

To find voltage = L*di/dt = 8*10^-6*20*10^-3/10^-6

= 160*10^-3 v.

= 160 milli volts.

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Answer: Option D

Explanation:

If the inductor are connected in parallel connection , then the formula for Equivalent Inductance is same as that of the Resistance.

i.e. (1/Leq)= (1/L1)+(1/L2)+(1/L3) 

So (1/Leq) = (1/5m)+(1/4.3m)+(1/0.6m)
(1/Leq) = 2099.2248

Therefore
Leq = 1/2099.2248 = 0.47 mH 
Which is less than 0.6 mH.

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Answer: Option D

Explanation:

Total inductance in series = L1+L2+L3
2.2+3.3+0.2= 5.5

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Answer: Option A

Explanation:

240 micro henry = 240*10^-6 = 0.000240H.

Therefore,

So we can write 0.000240H in milli Henry as 0.240mH.

So option A is correct.

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Answer: Option B

Explanation:

0.08 uH = 0.08 x 10^-6 H = 0.00000008 H

The question asked is 0.08 uH is LARGER than which of the given options.

So, we have to find the option that contains a value LESS than 0.08 uH.

Option A: 0.0000008 H > 0.00000008 H {Ruled out}
Option C: 0.000008 H > 0.00000008 H {Ruled out}
Option D: 0.00008 mH (or) 0.00000008 H == 0.00000008 H {Ruled out}

But, Option B: 0.000000008 H < 0.00000008 H {Answer}

Therefore, 0.08 uH is larger than Option B. Hence the answer.