The average value of a 12 V peak sine wave over one complete cycle is
Answer: Option A
Explanation:
Sin wave have both positive and nagetive peaks. So the average value is 0.
A sine wave of 15 kHz is changing at a faster rate than a sine wave with a frequency of
Answer: Option B
Because the frequency is cycle per second, upper frequency pass more cycle than lesser frequency. So 12 kHz is lesser than 15 kHz.
A signal with a 400 μs period has a frequency of
Explanation
f = 1/t = 1/400*10^-6 = 10000/4 = 2500 hz.
A sinusoidal current has an rms value of 14 mA. The peak-to-peak value is
Answer: Option C
Given Irms = 14 mA. We know that Irms = Ip/0.707. So Ip = Irms* 0.707. Ip = 14 ma* 0.707 = 19.79 ma. But this is simply a value of Ip. We also know that Peak to peak current = 2Ip. So Peak to peak current = 2*19.79ma = 39.6 mA.
If the peak of a sine wave is 13 V, the peak-to-peak value is
Peak to peak voltage = 2Vp =2*13=26v
