A 20 kHz pulse waveform consists of pulses that are 15 μs wide. The duty cycle
Answer: Option B
Explanation:
time t=1/frequency =1/20000 =0.00005 duty cycle=0.000015/0.00005 =0.3
and hence ans is 0.3*100 = 30%
A pulse waveform has a high time of 8 ms and a pulse width of 32 ms. The duty cycle is
Answer: Option A
Rise time=8ms. Total timeperiod=32ms. Dutycycle= (rise time/totaltimeperiod) *100. 8/32 (100) =25%.
If the rms current through a 4.7 kΩ resistor is 4 mA, the peak voltage drop across the resistor is
Answer: Option C
R =4.7kilo ohms=4700 ohms I=4mA=0.004 Amp V=IxR=0.004*4700=18.8 peak value=(square root 2)* v= 1.414*18.8=26.587
One sine wave has a positive-going zero crossing at 15° and another sine wave has a positive-going zero crossing at 55°. The phase angle between the two waveforms is
Phase angle is the difference between angles of two waveforms- so Wave 1 = 15 deg and wave 2 = 55 deg so Phase angle = 55-15 = 40 deg.
To produce an 800 Hz sine wave, a four-pole generator must be operated at
BY USING FORMULA, n=120f/P
N=(120*800)/4=24000 rpm Speed in rps = 24000/60 = 400rps
