Find branch current IR2.
Answer: Option C
Explanation:
(Va-12)/68-va/37-(va-4)/90 = 0. => 1665(va-12)-3060va-1258(va-4) = 0. => 5983va = 25012. => va = 4.180. Hence, IR2 = Va/37 = 4.180/37 = 112.97 = 113mA
What is the current through R2?
Answer: Option D
Applying kcl at node A and taking node B as refrence: (15-va)/68-va/30-(va-8)/100=0 va=5.1689v; Ir2=va/30=5.1689/30=0.172A=172mA;
Find the node voltage VA.
Easy way to calculate node analysis: i1+i2+i3 = 0 it is equal to:
((va-12)/49)+(va/24)+((va-6)/80)=0 ((va-12)(1920)+(va)(3920)+(va-6)(1176))/94080=0 va(7016)-30096=0 va=30096/7016 va=4.28
A galvanometer is a meter that measures small amounts of voltage.
Answer: Option B
Two equal-value resistors in series will divide the source voltage equally.
Answer: Option A
