KPMG Past Questions And Answers


1)

In the figure below, the area of square ABCD is 100, and the area of isosceles triangle DEC is 10. What is the distance from A to E?
2)

Consider the sequence 2, 6, 18, 54, 162,.… If the 48th term is a and the 51th is b, what is the value of  b/a?

Solution
In this geometric sequence the common ratio is 3, so: a51 = 3a50 = (3a49) = 9a49 = 9(3a48) = 27a48. Therefore, b/a = a51/a48 = 27. The answer is (E).
3)

What is the value of z, the number of seniors on teams as shown in the table below?

Solution
First we need to get t the total number of students which is: 180 ×  100/15 = 1,200.
Now we get y which is 40/100× 1200 = 480. Therefore to get z, we will add all the
number of student and subtract from the total: 180 + 120 + 480 + z = 1200  ⇒
780 + z = 1200   ⇒ z = 1200 – 780   ⇒ z = 420. The answer is (B).
4)

In the figure above, what is the value of a?

Since it is a straight angle, then the sum of a + a + a + a + a = 180. The sum of a = 5a, therefore the average is  180/5 = 36  ⇒ a = 36.

 The answer is (B).
5)

At central high school 50 girls play intramural basketball and 40 girls play intramural volleyball. If 10 girls play both sports, what is the ratio of the number who plays only volleyball?

Solution
To get the ratio of the number who plays only volleyball, we will divide the number of those that play volleyball from those that play only volley ball. Number of girls that plays volleyball = 40, since 10 girls plays both game,

then number of girls that play only volleyball = 40 – 10 = 30. Therefore: 40/30= 4/3 or 4:3 or 1.33.

The answer is 4:3 or 1.33

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