KPMG Past Questions And Answers


51)

The price of a can of soup was increased by 20%. How many cans can be
purchased for the amount of money that used to buy 300 cans?

 


Solution
Assume that a can of soup used to cost $1 and that it now cost $1.20 (20% more). Then 300 cans of soup used to cost $300. How many cans costing $1.20 each can be bought for $300: 300 ÷ 1.20 = 250.

52)

During a sale a clerk was putting new price tag on each item. On one radio, he accidentally raised the price by 15% instead of lowering the price by 15%. As a result the price on the tag was $45 too high. What was the original price, in dollar, of the radio?


Solution
If p represents the original price, the radio was priced at 1.15p instead of .85p. Since there was a $45 difference:45 = 1.15p - .85p = 0.3p p = 45 ÷ .30 = 150.

53)

If 25 students took an exam and 4 of them failed, what percent of them passed?


Solution
If 4 students failed, then the other 25 – 4 = 21 student passed, and 21/25= 0.84 =
84%.

54)

On a test consisting of 80 questions, Marie answered 75% of the first 60 questions correctly. What percent of the other 20 did she need to answer correctly for her grade on the entire exam to be 80%?


To earn 80% on the entire exam, Marie needs to correctly answer 64 questions (80% of 80). So far, she has answered 45 questions correctly (75% of 60). Therefore, on the last 20 questions she needs 64 – 45 = 19 correct answer; and 19/20 = 95%. The correct answer is D.

55)

9 is 1/3 % of what number?


9 =(1/3)x/100 = 1x/300 ⇒ x = 9 × 300 = 2700