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Workforce Numerical Past Questions and Answers


1)

John can read 72 pages per hour. At this rate, how many pages can he read in 72 minutes

Answer : B

Explanation:

Set up a proportion: 72 pages/1hr = 72 pages/60mins =xpages/72minutes
72 pages/60mins =xpages/72minutes
Therefore 72 x 72 = 60x
X = 5184/60
X = 86.4 (B)
2)

A hospital has enough pills on hand to treat 10 patients for 14 days. How long will the pills last if there are 35 patients.

Answer : A

Explanation:

This is a rate problem. The more the patients, the less the days the drugs can last. So Patients is indirectly proportional to Days (Patients α 1/Days)
Let P represent Pills
Let D represent Days
P α 1/D
P = K/D ( Where K = constant)
PD= K
10 x 14 = K
K = 140
Using the equation PD = K
For 35 patients, the pills will last for 35 x D = 140
D = 140/35 = 4 (A)
3)

The price of a can of soup was increased by 20%. How many cans can be purchased for the amount of money that used to buy 300 cans?

Answer : C

Explanation:

Assume that a can of soup used to cost N1 and that it now costs N1.20 (by 20% increase). Then 300 cans of soup used to cost N 300. Therefore, how many cans can be bought for N300?
N 300/1.20 = N 250 (C)
4)

If 25 students took an exam and 4 of them failed, what percent of them passed?

Answer : A

Explanation:

If 4 students failed,
then the other 25-4 = 21.
21 students passed, and 21/25 =0.84
84% (A)
5)

Judy is now twice as old as Adam but 6 years ago she was 5 times as old as he was. How old is Judy now?

Answer : B

Explanation:

Represent Adam with A
Represent Judy with J
Judy now is twice as old as Adam J = 2A
Six years ago J-6 = 5(A-6)

Therefore, J-6 = 5A – 30
J-6 = 5(J/2) – 30
Multiply through by 2
2(J-6) = 5J-60
2J-12 = 5J-60
-12+60 = 5J-60
48 = 3J
J = 48/3
J = 16 (B)

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