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Workforce Numerical Past Questions and Answers


Use the Table above to solve the following Questions:


36)

In 2009 what was the absolute difference between the Parent Company’s full-time employees and part-time employees (if Number of employees = Full-time employees + part-time employees)?

Step 1 – Calculate the total employees in 2009 1,614 + 962 + 1,412 + 1,583 + 1,029 = 6,600
Step 2 – Calculate the number of full-time employees
Number of employees = Full-time employees + part-time employees 6,600 = 100% = x% + 5%
Full-time employees = 95%
Step 3 – Calculate the difference in the % of part-time employees to full-time employees 95% - 5% = 90%
Step 4 – Calculate the difference 6,600 x 90% = 5,940

Thus the correct answer is (E) 5,940
37)

What % of the Parent Company’s total employees worked for Subsidiary 5 in 2006 (to the nearest whole %)?

Answer : D

Explanation:

Step 1 - Calculate the total number of employees across all 5 Subsidiaries
i.e. the Parent Company’s number of employees = 6,527
Step 2 – Calculate the % of Subsidiary 5 employees 980/6527 = 15.01%
Thus the correct answer is (D) 15%
38)

1 in 15 of the parent company’s part-time employees were managers in 2005 and 1 in 13 part-time employees were managers in 2007. What was the difference in the number of part-time managers in 2005 compared to 2007?

Answer : B

Explanation:

Step 1: Total employees for each year:

Total employees 2005 = 6,500

Total employees 2007 = 6,500

Step 2 Part-time employees for each year

Part-time employees for 2005  = 6,500 x 12% = 780

Part-time employees for 2007 = 6,500 x 8% = 520

Step 3 Managers =

2005= 780 / 15 = 52

2007= 520 / 13 = 40

Step 4 Difference = 52 – 40 = 12
Thus the correct answer is (B) 12 more
39)

In 2008 subsidiary company 4 comprised 2 regions with double the number of employees in one region compared to the other. If the ratio of male:female employees in the smaller region was 1:1.15, what was this region’s number of male employees?

Answer : A

Explanation:

Step 1 – Calculate the number of employees in the smaller region 1,548/3= 516 employees
Step 2 – Apply the 1:1.15 Male:Female ratio 516/2.15 = 240 male employees

hus the correct answer is (A) 240
40)

Between which three years was there an average of 1,553 employees for one of the Subsidiary Companies?

Answer : C

Explanation:

Step 1 – Looking at the employee totals there are only two Subsidiary Companies that could have an average of 1,553 employees across three years: Subsidiary Companies 1 and 4.

The answer options include Subsidiary Companies 1 and 4, as well as (E) None of these.
Step 2 - Calculate the average number of employees for answer options (A) – (D)

2005-2007 Subsidiary 1 = 1,565
2006-2008 Subsidiary 1 = 1,581
2007-2009 Subsidiary 4 = 1,553
2007-2009 Subsidiary 1 = 1,591



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